Solid Mechanics Reference

    Stress

    The internal forces and moments generally vary from point to point. Obtaining this distribution is of primary importance in mechanics of materials. The total force in a cross-section, divided by the cross-sectional area, is the stress. We use stress to normalize forces with respect to the size of the geometry.

    Units

    The units of stress can be found in the table below.
    MeasureSI systemUS system
    Force[\(N\)][\(lb\)]
    Area[\(m^2\)][\(in^2\)]
    StressPascal = [\(Pa\)] = [\(N/m^2\)]pound per square inch = [\(psi\)] = [\(lb/in^2\)]
    It is also important to recall some of the most common prefixes used to denote quantity.
    kiloPascal [\(kPa\)]\(10^3\) [\(Pa\)]
    megaPascal [\(MPa\)]\(10^6\) [\(Pa\)]
    gigaPascal [\(GPa\)]\(10^9\) [\(Pa\)]
    Typical sign convention for axial (normal) stress:
    • Tension:\( \sigma > 0 \)
    • Compression:\( \sigma < 0 \)

    Stress under general loading conditions

    We consider a homogeneous distribution of the internal force \( \Delta F \) over an infinitesimal area \( \Delta A \). The stress is defined by the infinitesimal force divided by the infinitesimal area.
    • Normal Stress: Defined by the intensity of the force acting NORMAL to \( \Delta A \)
    • Shear Stress: Defined by the intensity of the force acting TANGENT to \( \Delta A \)

    Average Normal Stress - Axial Loading

    Normal stress
    Here we assume that the distribution of normal stresses in an axially loaded member is uniform. Stress is calculated away from the points of application of the concentrated loads. Uniform distribution of stress is possible only if the line of action of the concentrated load \( P \) passes through the centroid of the section considered
    Average normal stress. #sts-ans
    $$ \sigma_{ave} = \frac{F}{A}\ $$
    where \( F \) is the internal resultant normal force and \( A \) is the cross-sectional area of the bar where the normal stress \( \sigma_{ave} \) is calculated.
    Non-uniform stress distribution
    Around the point where the load is applied, the stress distribution is non-uniform. Cross-sections farther away from the point load gradually have a more uniform distribution. When the distance is greater than the widest dimension of the cross-section (\( l > b \)), the stress distribution is uniform.

    Average Shear Stress

    Shear stress
    Obtained when transverse forces are applied to a member. The distribution of shear stresses cannot be assumed uniform. Common in bolts, pins and rivets used to connect various structural members.
    Average shear stress
    Average shear stress. #sts-tav
    $$ \tau_{ave} = \frac{V}{A}\ $$
    where \( V \) is the internal resultant shear force and \( A \) is the cross-sectional area of the bar where the shear stress \( \tau_{ave} \) is calculated. Example: Single Shear Determine the shear stress in the bolt.
    Single shear stress
    Single shear stress. #sts-sss
    $$ \tau_{ave} = \frac{P}{A}\ $$
    $$ \Sigma F_y = V-P = 0\ $$
    $$ V = P\ $$
    Example: Double Shear Determine the shear stress in the bolt.
    Double shear stress
    Double shear stress. #sts-dss
    $$ \tau_{ave} = \frac{P}{2A}\ $$
    $$ \Sigma F_y = 2V-P = 0\ $$
    $$ V = \frac{P}{2}\ $$

    Extra!

    Supplemental video:

    Stress Tensor

    Stress element

    The components of normal and shear stress can be combined into the stress tensor. This is a symmetric matrix representing the state of stress with respect to three directions.

    $$ T= \begin{bmatrix} \sigma_{x} & \tau_{xy} & \tau_{xz} \\ \tau_{yx}& \sigma_{y} & \tau_{yz} \\ \tau_{zx}&\tau_{zy}&\sigma_{z} \end{bmatrix} \ $$
    • Three normal stress components: \( \sigma_x, \sigma_y, \sigma_z \)
    • Six shear stress components: \( \tau_{xy} =\tau_{yx}, \tau_{xz}=\tau_{zx}, \tau_{yz}=\tau_{zy} \)

    Learn more about this topic on the Stress Transformation page.

    The first subscript describes the surface orientation in the normal direction. The second subscript describes the direction of the stress.

    Support Reactions

    Support reactions

    Allowable Strength Design

    Design Requirement: A structural design is intended to support and/or transmit loads while maintaining safety and utility: don't break. Strength of a structure reflects its ability to resist failure.
    • Ultimate load ( \( P_u \) ): force when specimen fails (breaks).
    • Ultimate normal stress ( \( \sigma_u \) ):
      $$ \sigma_u = \frac{P_u}{A}\ $$
    A structure is safe if its strength exceeds the required strength. Factor of Safety (FS): Ratio of structural strength to maximum (allowed) applied load (\( P_{all} \)).
    $$ P_{all} \le \frac{P_u}{FS}\ $$
    Similarly,
    $$ \sigma_{all} \le \frac{\sigma_u}{FS}\ $$